If it's not what You are looking for type in the equation solver your own equation and let us solve it.
c^2=8^2+17^2
We move all terms to the left:
c^2-(8^2+17^2)=0
We add all the numbers together, and all the variables
c^2-353=0
a = 1; b = 0; c = -353;
Δ = b2-4ac
Δ = 02-4·1·(-353)
Δ = 1412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1412}=\sqrt{4*353}=\sqrt{4}*\sqrt{353}=2\sqrt{353}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{353}}{2*1}=\frac{0-2\sqrt{353}}{2} =-\frac{2\sqrt{353}}{2} =-\sqrt{353} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{353}}{2*1}=\frac{0+2\sqrt{353}}{2} =\frac{2\sqrt{353}}{2} =\sqrt{353} $
| 227=99-w | | 4x×4x=16x^2 | | 10x-2=x+8 | | 3/4x+3(5)=12 | | 0.457=0.03x+0.002 | | (2x+20)+(3x+20)=180 | | (2x+20)+(3x+20)=360 | | 180=63-x+13 | | 3/4(x-4)=2(x+1) | | |7x|-7=21 | | 20+5x=9x | | 10+x/2=4x | | 4y´´-9y=0 | | 0=4x^2-48x | | 5-3x=x/4 | | -7(a+1)=3 | | 4m+2=2m+12 | | 3x^2+87=30x | | 320=5x(2x) | | 13=26x | | 320=10x^2 | | 320=5x•2x | | 6y-25=110+y | | 6/7=9/4x+2 | | 400x2-9.8x-17.64=0 | | 1/2+4y=8y-3/10 | | 312.25=a+0.25a | | 2x-9=x-18 | | 6x-5=7x+7-x | | (x-8)(x-7)=-8x+44 | | 21x-11=-26 | | 250b+250=2800 |